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Hi,

I have a question concerning PDEs with initial conditions. The general solution to my PDE is achieved by:

PDE:=diff(p(x,y,t),t)=(x-1)*k1*p(x,y,t)+(y-x)*k2*diff(p(x,y,t),x)+
(1-y)*k3*diff(p(x,y,t),y);

ans:=pdsolve(PDE);

However, I would like to achieve the solution for this PDE with the initial condition p(x,y,0)=x^n. I have read all the information I could find under the help menu. If there is no way to define the initial conditions directly in the pdsolve function, then how do I get the solution of the PDE with my initial conditions given the general solution achieved by pdsolve?

Thanks!

Patricia
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