Question: Solving system of equations

Hello,

 

I have the following system of equations to solve which is quite big.. Does anyone know how I can solve it faster or in a more simple way?

Thanks 

solve({(-(1/((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p))))*((0.002+0.001)*sin(-0.39)-(0.001+1*(e+p))*cos(-0.39)*(e*(-m+(0.68/d)+(0.599/g))+j*m)-(1/((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p))))*((0.001+1*(j+p))*sin(-0.39)-(0.002+0.001)*cos(-0.39))*(j*(-n+(0/i)+(-0.73/l))+e*n)))/(2*10)=-0.12, (-((0.002+0.001))*e/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*d)*(e*(-m+(0.68/d)+(0.599/g))+j*m)-((0.001+1*(j+p))*e)/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*d)*(j*(-n+(-0.73/l))+e*n)+(e*n)/d)/(2*10)=-0.069,  (-((0.002+0.001))*e/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*g)*(e*(-m+(0.68/d)+(0.599/g))+j*m)-((0.001+1*(j+p))*e)/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*g)*(j*(-n+(-0.73/l))+e*n)+(e*n)/g)/(2*10)=-0.079,   (-(0.001+1*(e+p))*j/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*i)*(e*(-m+(0.68/d)+(0.599/g))+j*m)-(-(0.002+0.001))*j/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*i)*(j*(-n+(-0.73/l))+e*n)-(j*m)/i)/(2*10)=-0.003,   (-(0.001+1*(e+p))*j/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*l)*(e*(-m+(0.68/d)+(0.599/g))+j*m)-(-(0.002+0.001))*j/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*l)*(j*(-n+(-0.73/l))+e*n)-(j*m)/l)/(2*10)=-0.023,  -(1*c*(1/((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p))))*((0.001+1*(j+p))*sin(-0.39)-(0.002+0.001)*cos(-0.39))*e)/d=-0.109,   -(1*c*(-(0.002+0.001))*j/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*i)*e)/d=0.0003, -(1*f*(1/((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p))))*((0.001+1*(j+p))*sin(-0.39)-(0.002+0.001)*cos(-0.39))*e)/g=-4.928,  -(1*f*(-(0.002+0.001))*j/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*l)*e)/g=0.013,  -(1*h*(1/((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p))))*((0.002+0.001)*sin(-0.39)-(0.001+1*(e+p))*cos(-0.39))*j)/i=-0.058,    -(1*h*((0.002+0.001))*e/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*d)*j)/i=-0.0005,    

-(1*k*(1/((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p))))*((0.002+0.001)*sin(-0.39)-(0.001+1*(e+p))*cos(-0.39))*j)/l=-1.39, -(1*k*((0.002+0.001))*e/(((0.002+0.001)^2+(0.001+1*(e+p))*(0.001+1*(j+p)))*d)*j)/l=-0.011}, [c,d,e,f,g,h,i,j,k,l,m,n,p])

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