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Question: RootOf and _Z... Help !

Question: RootOf and _Z... Help !

danlun 15 Maple 15
October 30 2013
1

q[1] = sqrt(x)*alpha-lambda(sqrt(x)*alpha-lambda*q[1]*q[3]-p[2])*(sqrt(x)*alpha-lambda*q[1]*q[2]-p[3])-p[1]

I am looking for q[1] solution. When I solve for q[1], maple gives me following answer:

q[1] = RootOf(-_Z+sqrt(x)*alpha-lambda(sqrt(x)*alpha-lambda*_Z*q[3]-p[2])*sqrt(x)*alpha+lambda(sqrt(x)*alpha-lambda*_Z*q[3]-p[2])*lambda*_Z*q[2]+lambda(sqrt(x)*alpha-lambda*_Z*q[3]-p[2])*p[3]-p[1])

Is it possible to obtain a classical solution for the calculations above. (can not understand the meaning of: RootOf and _Z. I need q[1] in order to solve further in my system of eqautions for  q[2],  q[3]

 

could you help me please to find a solution for this issue...
I would like to thank you in advance 
Best regards,

D.L.
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