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Question: how i can get more simple form

Question:how i can get more simple form

matmxhu 75 Maple 17
simplify assuming
December 05 2013
0


 hi,i get a formula like this ,i want to simplify the expression under some assumptions, but ,i can't  do this.may you can help me.

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-(-2*N__1*`ω__2`*`ω__1`^2*lambda-8*N__2*lambda^3*`ω__2`-sqrt(4*N__1^2*lambda^2*`ω__1`^2*`ω__2`^2+16*N__1*N__2*lambda^4*`ω__2`^2+N__1*N__2*`ω__1`^2*`ω__2`^4+4*N__2^2*lambda^2*`ω__2`^4)*`ω__1`)/(4*N__1*lambda*`ω__1`^2*`ω__2`+16*N__2*lambda^3*`ω__2`)

-(-2*N__1*`ω__2`*`ω__1`^2*lambda-8*N__2*lambda^3*`ω__2`-(4*N__1^2*lambda^2*`ω__1`^2*`ω__2`^2+16*N__1*N__2*lambda^4*`ω__2`^2+N__1*N__2*`ω__1`^2*`ω__2`^4+4*N__2^2*lambda^2*`ω__2`^4)^(1/2)*`ω__1`)/(4*N__1*lambda*`ω__1`^2*`ω__2`+16*N__2*lambda^3*`ω__2`)

 (1)
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`assuming`([simplify(-(-2*N__1*`ω__2`*`ω__1`^2*lambda-8*N__2*lambda^3*`ω__2`-(4*N__1^2*lambda^2*`ω__1`^2*`ω__2`^2+16*N__1*N__2*lambda^4*`ω__2`^2+N__1*N__2*`ω__1`^2*`ω__2`^4+4*N__2^2*lambda^2*`ω__2`^4)^(1/2)*`ω__1`)/(4*N__1*lambda*`ω__1`^2*`ω__2`+16*N__2*lambda^3*`ω__2`), 'size')], [all, positive])

(1/4)*(4^(1/2)*((N__1*lambda^2+(1/4)*N__2*`ω__2`^2)*`ω__2`^2*(N__1*`ω__1`^2+4*N__2*lambda^2))^(1/2)*`ω__1`+2*lambda*`ω__2`*(N__1*`ω__1`^2+4*N__2*lambda^2))/(lambda*`ω__2`*(N__1*`ω__1`^2+4*N__2*lambda^2))

 (2)
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`assuming`([combine((1/4)*(4^(1/2)*((N__1*lambda^2+(1/4)*N__2*`ω__2`^2)*`ω__2`^2*(N__1*`ω__1`^2+4*N__2*lambda^2))^(1/2)*`ω__1`+2*lambda*`ω__2`*(N__1*`ω__1`^2+4*N__2*lambda^2))/(lambda*`ω__2`*(N__1*`ω__1`^2+4*N__2*lambda^2)), 'size')], [N__1 > 0, N__2 > 0, `ω__1` > 0, `ω__2` > 0, lambda > 0])

(1/4)*(`ω__1`*`ω__2`*((4*N__1*lambda^2+N__2*`ω__2`^2)*(N__1*`ω__1`^2+4*N__2*lambda^2))^(1/2)+2*lambda*`ω__2`*(N__1*`ω__1`^2+4*N__2*lambda^2))/(lambda*`ω__2`*(N__1*`ω__1`^2+4*N__2*lambda^2))

 (3)
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