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Question: How do I let Maple work with the positive value's for the intersect in 2 equations?

Question:How do I let Maple work with the positive value's for the intersect in 2 equations?

jochemo 10 Maple 2016
solve intersection
April 09 2017
2

Hi all,

I am working on a Maple file to find the right force excerted in a specifik angle (theta). This is the script Maple than has to work out:

 

eq4 := Fh1 = (1/2)*(solFh2*sqrt(2)-40)/sin(theta);
eq5 := Fh1 = (1/2)*(solFh2*sqrt(2)-100)/cos(theta);
sol := solve({eq4, eq5}, {Fh1, theta});

Next it gives me the answers as following:

sol := {Fh1 = 121.6477702, theta = .9606764638}, {Fh1 = -121.6477702, theta = -2.180916190}

Which is correct: I get a force (Fh1 = ± 121.6477...) with 2 angles (theta = .9696... or theta=-2.1809...)

 

If i want to continue working with Fh1 it gives an error saying it has 2 values for it (obviously a positive and a negative value). Is there a way to continue working with the positive values of Fh1 and theta?

 

I was thinking of solving the intersect equation on the positive 'theta'-axis in a form like:

 

sol := solve({eq4, eq5}, {Fh1, theta>0}); as theta is my horizontal axis and a positve theta gives me a positive Fh1 but Maple doesn't work that straightforward. 

 

Thanks a lot!
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