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Question: complex and imaginary or real and imaginary number comparison: is it not possible?

Question:complex and imaginary or real and imaginary number comparison: is it not possible?

Ramakrishnan 399 Maple 2017
coulditbe
October 10 2017
0

Can any one disprove maple answer in the attached document?
If not, what is the conclusion?
 

restart

coulditbe(3*I > 0)

false

 (1)

coulditbe(3*I > 0)

false

 (2)

coulditbe(3*I < 0)

false

 (3)

coulditbe(-2+3*I = 0)

false

 (4)

coulditbe(abs(I) > 0)

true

 (5)

true

 (6)

coulditbe(2+3*I < 0)

true

 (7)

``

``

What is your opinion?

My opinion from the above is : When a is real and b is complex, a and b can not be compared.

Like number of goats and number of lions  can not be added to give an answer in number of lions alone or number of goats alone!!
Riemann's function Zeta is a function of Complex number

 

solve(abs(Zeta(s+2*I)) = 0, s)

-2*I+RootOf(Zeta(_Z))

 (8)

"(->)"

-2.0000-2.*I

 (9)

NULL

solve(Zeta(s+2*I) = 0, s)

-2*I+RootOf(Zeta(_Z))

 (10)

"(->)"

-2.0000-2.*I

 (11)

What does the above results convey??

Am I correct if i state that 's' should be a complex number only and not a real number.


 

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