Advanced Search

Question: Please Help Me to understand this

Question:Please Help Me to understand this

Adam Ledger 360 Maple
syntax mod
March 17 2018
0

I really need help to understand this i know it is a non associative operation but i just cannot see how no operator is handled in the computation here


 

> 

A := (rand(1 .. 100))():

8

  

8

  

9424

 (1)
> 

A := (rand(1 .. 100))():

33

  

33

  

33

 (2)
> 

``


 

Download please_HELP.mw

This will be my last question i promise then i will go to bed for a week.

(its what happens when the government decide after 20 years they are going to make it illegal for me taking stimulants therefore must purchase from non pharmacy sources and can barely afford 1 out of every 2 weeks supply, they charge $6 AUD per tablet on the street so, i was prescribed 8 per day, i earn $250 a week, so yes, that is more than all of my money)

Sorry, just want to repeat that as much as possible to embarass my government an infintesimal amount in public forums, never go to australia, my country is a piece of shit and the people here are on the most part uncivilized socially backward morons 

 

 

Edit: Here is a better worksheet for you comrades 
 

> 

restart
> 

X := proc (A, B) options operator, arrow; (`mod`((`mod`(A, n))*(`mod`(B, n)), n))((`mod`(A, n))*(`mod`(B, n))) end proc:
> 

Y := proc (A, B) options operator, arrow; (`mod`((`mod`(A, n))*(`mod`(B, n)), n))*(`mod`(A, n))*(`mod`(B, n)) end proc:
> 

is(X(A, B) <> Y(A, B))

false

 (1)
> 

is((`mod`((`mod`(A, n))*(`mod`(B, n)), n))((`mod`(A, n))*(`mod`(B, n))) <> (`mod`((`mod`(A, n))*(`mod`(B, n)), n))*(`mod`(A, n))*(`mod`(B, n)))

false

 (2)
> 

A := (rand(1 .. 100))():
> 

is((`mod`((`mod`(A, n))*(`mod`(B, n)), n))((`mod`(A, n))*(`mod`(B, n))) <> (`mod`((`mod`(A, n))*(`mod`(B, n)), n))*(`mod`(A, n))*(`mod`(B, n)))

true

 (3)
> 

is(X(A, B) <> Y(A, B))

true

 (4)
> 

``


 

Download helpPlz.mw
Please Wait...