Question: Math help required

Now, I'm not the professional here, you guys are, since this is how the software has been built to produce this code automatically as i can only assume to be educational purposes for the user, concerning the analytic extension of the factorial on C, the gamma function. 

I feel that doing this is in no way helping or promoting your product, clearly despite the idea indeed having merit, it is not applicable to the extent it has been written into your convert function, and look, show me the mathematics of why it makes sense to have things designed this way. 

 

I am not saying i know anything important or am trying to be insulting, I just feel like this is some kind of joke to be honest, i mean how can for the most part the software be an exceptional in terms of computational power, and then this garbage is thrown at me? yeah just silly.

 


 

product(n/k^2-1/(k*n), k = 1 .. n-3)

-(-1)^(n-2)*GAMMA(-n^2+n-2)*(1/n)^(n-2)*n/(GAMMA(n-2)^2*GAMMA(-n^2+1))

(1)

seq(product(n/k^2-1/(k*n), k = 1 .. n-3), n = 3 .. 10)

1, 15/4, 138/25, 6545/1296, 16215/4802, 2342949/1310720, 7512505/9565938, 29537761/100000000

(2)

seq(convert(-(-1)^(n-2)*GAMMA(-n^2+n-2)*(1/n)^(n-2)*n/(GAMMA(n-2)^2*GAMMA(-n^2+1)), 'factorial'), n = 3 .. 10)

Error, (in GAMMA) numeric exception: division by zero

 

Um there is no gamma it was converted to a factorial.....? but ok....

convert(-(-1)^(n-2)*GAMMA(-n^2+n-2)*(1/n)^(n-2)*n/(GAMMA(n-2)^2*GAMMA(-n^2+1)), 'factorial')

-(-1)^(n-2)*factorial(-n^2+n-3)*(1/n)^(n-2)*n/(factorial(n-3)^2*factorial(-n^2))

(3)

seq(-(-1)^(n-2)*factorial(-n^2+n-3)*(1/n)^(n-2)*n/(factorial(n-3)^2*factorial(n^2)), n = 100 .. 100)

Error, numeric exception: division by zero

 

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