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Question: calculate integral

Question:calculate integral

torabi 85 Maple 2018
integration
October 30 2018
0

hi.

I can not gain answer for integral.

Best

int.mw
 

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PDE := (12*kappa^2*psi^2*(-upsilon^2+1)*((3*Pi^2*Q^2*(nu*psi^2+1)/(32*(-nu^2+1))+Q^2*(Pi^2*cos(2*Pi*y)/(8*psi^2)+psi^2*cos(2*Pi*x)*Pi^2*cos(2*Pi*y)/(4*(psi^2+1)^2)+Pi^2*cos(4*Pi*y)/(32*psi^2)+psi^2*cos(2*Pi*x)*Pi^2*cos(4*Pi*y)/(2*(4*psi^2+1)^2)+psi^2*cos(4*Pi*x)*Pi^2*cos(2*Pi*y)/(8*(psi^2+4)^2)))*(2*Q*Pi^2*sin(Pi*x)^2*cos(Pi*y)^2-2*Q*cos(Pi*x)^2*cos(Pi*y)^2*Pi^2)+(2*Q*cos(Pi*x)^2*Pi^2*sin(Pi*y)^2-2*Q*cos(Pi*x)^2*cos(Pi*y)^2*Pi^2)*(3*Pi^2*Q^2*(psi^2+nu)/(32*(-nu^2+1))+Q^2*((1/8)*psi^2*cos(2*Pi*x)*Pi^2+psi^2*cos(2*Pi*x)*Pi^2*cos(2*Pi*y)/(4*(psi^2+1)^2)+(1/32)*psi^2*cos(4*Pi*x)*Pi^2+psi^2*cos(2*Pi*x)*Pi^2*cos(4*Pi*y)/(8*(4*psi^2+1)^2)+psi^2*cos(4*Pi*x)*Pi^2*cos(2*Pi*y)/(2*(psi^2+4)^2)))-8*Q^3*cos(Pi*x)*cos(Pi*y)*Pi^2*sin(Pi*x)*sin(Pi*y)*(-psi^2*Pi^2*sin(2*Pi*x)*sin(2*Pi*y)/(4*(psi^2+1)^2)-psi^2*Pi^2*sin(2*Pi*x)*sin(4*Pi*y)/(4*(4*psi^2+1)^2)-psi^2*Pi^2*sin(4*Pi*x)*sin(2*Pi*y)/(4*(psi^2+4)^2)))+beta*V^2/(1-Q*cos(Pi*x)^2*cos(Pi*y)^2)^2-8*Q*Pi^4*cos(Pi*x)^2*cos(Pi*y)^2+8*Q*Pi^4*sin(Pi*x)^2*cos(Pi*y)^2-2*psi^2*(4*Q*Pi^4*sin(Pi*x)^2*sin(Pi*y)^2-4*Q*Pi^4*sin(Pi*x)^2*cos(Pi*y)^2-4*Q*cos(Pi*x)^2*Pi^4*sin(Pi*y)^2+4*Q*Pi^4*cos(Pi*x)^2*cos(Pi*y)^2)-psi^4*(-8*Q*cos(Pi*x)^2*Pi^4*sin(Pi*y)^2+8*Q*Pi^4*cos(Pi*x)^2*cos(Pi*y)^2))*(1-Q*cos(Pi*x)^2*cos(Pi*y)^2)^2*cos(Pi*x)^2*cos(Pi*y)^2

int(int(PDE, y = -1/2 .. 1/2), x = -1/2 .. 1/2)


 

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