Question: Solving Equations Involving Radicals

Hi,

I'm only getting one Answer instead of two (see below).

Thanks in Advance


 

Example 4: Solving Equations Involving Radicals

 

"ex4a(x):=sqrt(2 x+7)-x-2"

proc (x) options operator, arrow, function_assign; sqrt(2*x+7)-x-2 end proc

(1.1)

"->"

 

NULL

NULL

NULL

sqrt(2*x+7)-x-2

(2*x+7)^(1/2)-x-2

(1.2)

"(->)"

[[x = 1]]

(1.3)

NULL

2*x+7 = x^2+4*x+4

2*x+7 = x^2+4*x+4

(1.4)

"(->)"

[[x = -3], [x = 1]]

(1.5)

x^2+2*x-3 = 0NULL

x^2+2*x-3 = 0

(1.6)

(x+3)*(x-1) = 0

(x+3)*(x-1) = 0

(1.7)

"(->)"

[[x = -3], [x = 1]]``

(1.8)

``


 

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