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Question: How do I solve using Newton's Method to calculate the root(3) to 6 decimal places. Consider the function f(x) = (x^2) - 3

Question:How do I solve using Newton's Method to calculate the root(3) to 6 decimal places. Consider the function f(x) = (x^2) - 3

Jwiseknows 10 Maple 2019
rootfinding homework numeric newton do-my-homework-for-me
October 10 2020
1

To solve this, I got this far but am not sure where to go next?

 

f2 := x^2 - 3;
f2d := diff(f2, x);
                              2    
                             x  - 3
                              2 x

set value for x0, number precision

x0 := 3;
eps := 0.1*10^(-5);
                               3
                            0.000001
 
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