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Question: How to remove a=a from solutions using subsindents and applyrule?

Question:How to remove a=a from solutions using subsindents and applyrule?

nm 8552 Maple 2020
October 26 2020
0

sometimes solve returns solution of the form

restart;

#eqs:=.....
#sol:=solve(eqs,{v[1],v[2],v[3]});

sol:={v[1]=t,v[2]=3/2*t,v[3]=v[3]};

And wanted to remove all those that represnt arbitrary solution, which is v[3]=v[3] above.

I could do this using

remove(x->lhs(x)=rhs(x),sol);

which gives

{v[1]=t,v[2]=3/2*t};

But as an excersise, I could not figure how to do the same using subsindent (where I wanted to replace v[3]=v[3] with {} or NULL,. and also using applyrule.

Is it possible to do the same as above but using subsindent and applyrule (which is similar to patmatch)? 
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