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Question: inert % does not obey order of operations

Question:inert % does not obey order of operations

Stretto 235 Maple
inert precedence
March 14 2021
0

4 %+ 3 %* 2;
                        %*(%+(4, 3), 2)

= (4+3)*2

It makes using % very difficult in complex expressions because one has to constantly use a ton of paranethesis just to get things to work out.

1 + 4%^3  %* 2 %- 6 %/ 4;

1 + ((((4 %^ 3) %* 2) %- 6) %/ 4)

= 1 + (4^3*2 - 6)/4
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