T(t) = 20 + 74e (-ln(.4t) / 2)

Question:T(t) = 20 + 74e (-ln(.4t) / 2)

Posted: evielam 8 Product: Maple

February 25 2009

A hot piece of steel which is 94 degrees C is placed in a room that

is kept at a constant temperature of 20 degrees C. The steel begins to cool; its

temperature t hours after being placed in the room is given by

T(t) = 20 + 74e

(a) How long before the steel reaches 22 degrees?

(b) Graph T(t).

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