Question: How to differentiate e^sin(s*t)?

I would use the chain rule twice:

f(s,t) = e^u

u = sin(s*t);

u = sin(v);

v = s*t

v' = s;

u' = cos(s*t*)*s

f' = e^cos(s*t)*s

Maple adds *ln(exp), what's wrong with my way?

complete maple output: exp^sin(s*t)*cos(s*t)*t*ln(exp)

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