Advanced Search

Question: To plot a plane parrallel to a vector that goes though a point

Question:To plot a plane parrallel to a vector that goes though a point

maplesyrup06 8 Maple
geometry parallel
September 17 2007
0
hello everyone, I'd really appreciate your help. I have to finish a maple assignment within a couple of days and i've been stuck on this question that wants me to find a plane parrallel to a vector that goes though a point. The instructor gave me the following example [code] Example 6. Find the equation of the plane perpendicular to the vector ( 5, 1, -2 ) and passing through the point ( 0, 1, -1 ). Make a plot of this plane. We use the point-normal form of the equation of a plane: dotprod([5,1,-2],[x-0,y-1,z-(-1)])=0; _ _ _ 5 x - 3 + y - 2 z = 0 eqn:=solve(%,z); 5 3 1 - x - - + - y 2 2 2 plot3d(eqn,x=-5..5, y=-5..5, axes=framed); [/code] so this is what i tried out: crossprod([5,1,-2],[x-0,y-1,z-(-1)])=0; i've gotten an answer in the square brackets and it is equal to zero... so something like this: [ ... ] = 0 then i typed out: eqn:=solve(%,z); but then i would get the error: Error, (in solve) invalid arguments I figured that if i tried to use to same method for the cross product, i would get a parallel plane instead of a perpendicular one. So what am i doing wrong here? Is there a completely different approach (a long and more complicated one?) or is there a different way to solve for the cross product (and i mean different syntax by that). I've just got a new idea... should i just solve it using dotprod(...)=(unit vector) ???????????
Please Wait...