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Question: How do I substitute functions with parameters into differential equations?

Question:How do I substitute functions with parameters into differential equations?

Nathan 0 Maple
June 28 2010
0

I appreciate that maple can solve equations so quickly, but i would like to solve the equation myself and only use the basic features of maple so that I can practice the theory. For example:

for the differential equation y'' + 3y' + 2y = 0 

I would like to assume y = ce^rt then plug it in and get something like

c*(r^2*e^rt + 3r*e^rt + 2e^rt) = 0

 

maple runs into problems regarding:

-whether the parameters are functions or constants

-quantification of c and t versus r

 

how do i substitute a function for y?

how do i tell maple what i mean by c,r,t, and y?

Is there a way to make assumptions as I go along with the computation?

 

thanks,

nathan
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