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Question: solve _C1*sin(lambda*L)

Question:solve _C1*sin(lambda*L)

Alger 524 Maple 14
solve
October 20 2010
1

Hi,

When I solve this equation

Y(lambda):=_C1*sin(lambda*L);

solve(Y(lambda)=0,lambda);

Where _C1 and L are constants, I get 0.

But the solution of this equation which is easy is lambda=n*Pi/L where n=1,2,3,...

Why?

Thanks
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