In the Help section under procedures (or proc) it states:
argseq - the formal parameter names
I just wondered about the use of the word 'formal'.
eg in this simple Maple code
maxim:=proc (a,b,c,d)
max(a,b)+max(c,d)
end proc:
maxim(2,3,5,4);
. . . the formal parameters are a, b, c, d. Is the word 'formal
' being used as "officially recognised" and a=2, b=3 etc. (ie the
order is important or is there
some deeper meaning? I'd appreciate a short example of a proc using
something else besides variable values, or Null.
Thanks
David

Ok, I have the following equations: c'[t] = a[t]*b[t]*k1 - c[t]*k2, a'[t] = (-a[t])*b[t]*k1 + c[t]*k2, b'[t] = (-a[t])*b[t]*k1 + c[t]*k2, c[0] =0, a[0] =10, b[0] =10. I have data for concentration of "c" at all time intervals from 0-16. Here is the data: {0, 0}, {1, 4.98112}, {2, 6.61986}, {3, 7.42423}, {4,7.89529}, {5, 8.20004}, {6, 8.41008}, {7, 8.56123}, {8,8.67342}, {9, 8.7586}, {10, 8.82442}, {11, 8.87595}, {12, 8.91671}, {13, 8.94923}, {14, 8.97535}, {15, 8.99643}, {16, 9.01351}. I need Maple to Solve the ODE's and optimize the values for k1 and k2 to fit the data usins a least-square method or something along the lins of that. Can someone send me the code for that?

We were wondering if you could help us with a question to Maple: We have converted a C code directly into Maple code and have found that Maple runs about a thousand times slower than the C version (the code is a numerical simulation). 1) Why is this so? 2) How do we make it run faster?

Hi, All, I'm a Maple primer. I want to solve an ODE numerically and then save the data to file. I use: dsol := dsolve({deq,ic}, numeric, range=0..100); or dsol := dsolve({deq,ic}, numeric, range=0..100, output=operator); then how can I print the formated data for some specified t (=1..100, for example) to a data file? Thanks. David

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What can I do?

Florian

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A student in my PDE class asked about having two functions in animation at the same time. Here is how I suggested doing this: > f:=(t,x)->sin(t)*x*(1-x); > g:=(t,x)->cos(t)*x*(1-x); > N:=50; > for n from 0 to N do J[n]:=plot([f(2*Pi*n/N,x),g(2*Pi*n/N,x)],x=0..1): od: n:='n': > plots[display]([seq(J[n],n=0..N)],insequence=true); Is there a simpler way? Jim Herod

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