@asa12 

limit h tends to exp(x*y) where y=0,1

ln(x/h)

i am thinking the limit can be changed

@Kitonum 

I am thinking whether can ask 

IBM Watson 

to think diff operator from

F(s) = 1

F(F(s)) = 0

if computer can think this, 

it may think this impossible question

i am thinking whether it is another limit like diff(x,t) but the definition is change

@Kitonum 

F(s) = 1

F(F(s)) = 0

if you do not know diff(x,s), normal human think it is impossible

may be impossible, not exist this operator

If change to F(exp(t)) = 2*t, is it possible?

i am still thinking how to out of a black box.

@Carl Love 

the ordering is changed after first time run it

how to sort the result by the key string?

if result is ["1234"=1,"5678"=2]

@Joe Riel 

Kmap solver but i expect 2 or more outputs, as i know that there is software in linux but not convenient to automate

i would like to apply in this application for example, two english words with length 5, such as power and maple, convert to binary having the same length, would like to find a logic or binary number which can output two words at the same time

http://www.32x8.com/var3.html

@Carl Love 

succeed after remove decimal

thanks

@Carl Love 

error, when convert expect 2nd argument prec, to be type posint

but received decimal

@Carl Love 

how about how to reverse to find back binary from a character?

@Carl Love 

How about maximum factor?

@asa12 

in fact, i pass system as parameters because the number of equations are different among the systems

@John Fredsted 

getParams := proc (expr::function) 
local s, r;
s, r := selectremove(type, [op(expr)], function); 
if s <> [] then getParams(s[]), r[] else s[], r[] end if 
end proc;

in this case, not correct
getParams(AA(MM(AA(X1, X2), B2), MM(AA(B2, X3), X5)));
X1, X2, B2
 

@tomleslie 

thank you very much, it helps a lot

@tomleslie 

i am not asking how to dsolve or solve equation

i am asking a programming question about maple how to pass a system which has variables dependent on the local variable inside a function

because there is a need to hard code a system inside a function every time

it seems impossible to use function,

i plan not to use function and write the for loop directly in global instead of local

@roman_pearce 

if (0,0,0) is the solution which is a normal set, dot product of [z] and 0 is 0

why it do not return this solution?

@roman_pearce 

hello 1,2,3

are just 3 polynomials equations in terms of x, y, z

groebner basis result is one variable, [z]

would like to find normal set which perpendicular to groebner basis