Marvin Ray Burns

 I've been using Maple since 1997 or so.

MaplePrimes Activity


These are Posts that have been published by Marvin Ray Burns

 Consider the sequence of divergent series in part evaluated by the following maple input.

 

f1 := seq((1-a)*(1/2)+sum((-1)^n*(n^(1/n)-a), n = 1 .. infinity), a = 1/10 .. 9*(1/10), 1/10): evalf(f1);

 

and

 

f2 := `$`((1-a)*(1/2)+sum((-1)^n*(n^(1/n)-a), n = 1 .. infinity), a = 2 .. 10): evalf(f2);

The Maple output, which is the MRB constant

See the following PDF for the geometry of the MRB constant.

http://www.marvinrayburns.com/what_is_mrb.pdf

If you have any questions, I would like to hear them.

Marvin Ray Burns



In the blog MRB Constant-D I noticed a peculiar outcome to several sets of equations involving f(n) = sin((a+b*floor(n))*Pi/M), where M is a constant to be explored, b is a number to be found and a is a "starting value" that causes f(n) ~=  -1, 0 or 1.

I want to report some progress in finding a closed-form for the MRB constant.

I found a sequence of closed-forms involving the MRB that gives "0." with interesting accuracy far beyond machine precision. To see it for yourself, simply plot 1 + Sin[Pi*(5060936308 + 78389363*Floor[n])/m],
where m is the MRB Constant, for n in any given domain. It is


Download int_vs_sum_for_mr.mw

Looking at the attached worksheet,

it appears that the absolute value, minus 1/2, of the integral of (-1)^x*x^(1/x) from 1 to infinity would equal the partial sum of (-1)^x*x^(1/x) from 1 to where the upper summation is even and growing without bound [0]. Is anyone interested in improving or disproving this conjecture? 

 

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