jean-jacques

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14 years, 337 days

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These are replies submitted by jean-jacques

Dear DuncanA, thanks for the advice. But I am not done yet.

 

After

 

solu := solve({x+y=a, x-y=b}, {x, y});

 

I would like to be able to use  solu[1] and solu[2] for additional symbolic computation. To obtain for example

 

> solu[1]/solu[2];

 

But I get an error message:

 

> solu[1]/solu[2];

Error, (in simpl/reloprod) invalid terms in product: (y = -(1/2)*b+(1/2)*a)^-1

Kind regards,

 

Jean-Jacques

As I do not know much about Maple, I was wondering if using  commands like "assume"  (and several other that I do not know yet)  would be of some help.  I thought it was possible to have IF (or somethin like that) and SUM (and not ADD) working together as I wanted.

Mr Joe Riel, thanks a lot for the explanation.

 

Kindest regards,

 

Jean-Jacques

As I do not know much about Maple, I was wondering if using  commands like "assume"  (and several other that I do not know yet)  would be of some help.  I thought it was possible to have IF (or somethin like that) and SUM (and not ADD) working together as I wanted.

Mr Joe Riel, thanks a lot for the explanation.

 

Kindest regards,

 

Jean-Jacques

Dear Robert, Thanks a lot for the hint.

Dear Hinryk. Your suggestions is very useful to start for a solution.. You defined in the beginning j:=0, adn keeping this in memory simplifies the computation. However my problem is when j=0..1. Probably I would need to split the terms in the way in a case j=0, I get some conditiosn, and for j=1 another conditions.  However that is equivalent to evaluate "with paper and pen". Now, my problem is to use commands of Maple, because I need to include several j's (j1, j2, ..jM) and several ks.[But this will be in a serie of other posts]

 

I am grateful for all the help and hints.

 

Kindest regards and than you again,

 

Jean-Jacques

Dear Robert, Thanks a lot for the hint.

Dear Hinryk. Your suggestions is very useful to start for a solution.. You defined in the beginning j:=0, adn keeping this in memory simplifies the computation. However my problem is when j=0..1. Probably I would need to split the terms in the way in a case j=0, I get some conditiosn, and for j=1 another conditions.  However that is equivalent to evaluate "with paper and pen". Now, my problem is to use commands of Maple, because I need to include several j's (j1, j2, ..jM) and several ks.[But this will be in a serie of other posts]

 

I am grateful for all the help and hints.

 

Kindest regards and than you again,

 

Jean-Jacques

Dear Hirnyk 988,

 

I think I am very close to verify my results (obtaining with paper and pen). But my question is

 

1. How to find the value of S0 (before taking the limit)  when

x+y<1/2  (x, y both positives)?

 

AND

 

2. How to find the value of S0 (before taking the limit)  when

1/2  <  x+y <  1/2  (x, y both positives)?

 

Thanks a lot for your attention,

 

Jean-Jacques

 

Dear Hirnyk 988,

 

I think I am very close to verify my results (obtaining with paper and pen). But my question is

 

1. How to find the value of S0 (before taking the limit)  when

x+y<1/2  (x, y both positives)?

 

AND

 

2. How to find the value of S0 (before taking the limit)  when

1/2  <  x+y <  1/2  (x, y both positives)?

 

Thanks a lot for your attention,

 

Jean-Jacques

 

Dear hyrnik 988, thanks a lot for the answer.

 

Jean-Jacques

Dear hyrnik 988, thanks a lot for the answer.

 

Jean-Jacques

Thanks for the solutions.

Jean-Jacques

Thanks for the solutions.

Jean-Jacques

Thanks a lot for the solutions to my problems.

Kind regards,

 

jean-Jacques

Thanks a lot for the solutions to my problems.

Kind regards,

 

jean-Jacques

As  I am getting familiarized with Maple14.. I did copy the commands, but does not generate any sequence.

Am I doing something wrong?

Kind regards,

 

Jean-Jacques

As  I am getting familiarized with Maple14.. I did copy the commands, but does not generate any sequence.

Am I doing something wrong?

Kind regards,

 

Jean-Jacques

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