Hi:

how can i convert one nonlinear second order ode to first order in maple?

Hi:

What methods to solve system nonlinear ordinary differential equations in maple?I follow a method to solve system nonlinear ode second order that very fast answer me?

Hi users:

i will solve the system of equations with laplace method in maple,every body can help me?

EQ1:= -1.383117237*10^(-9)*q2(T)+4.345190953*10^(-9)*q1(T)+3.643814673*10^(-17)*(diff(q1(T), T, T)) = 0
EQ2 := 3.522088316*10^(-10)*q2(T)-1.106493791*10^(-9)*q1(T)-6.094634321*10^(-16)*q4(T)+6.094634321*10^(-16)*q5(T)+2.429209782*10^(-24)*(diff(q2(T), T, T)) = 0
EQ3 := 1.378642186*10^(-8)*q3(T)+4.570975739*10^(-12)*q4(T)+4.570975739*10^(-12)*q5(T)+3.643814673*10^(-17)*(diff(q3(T), T, T)) = 0
EQ4 := .6366197720-.5208074999*(diff(q5(T), T))-0.5140163994e-5*q4(T)-4.092794921*q5(T)+.7896341498*(diff(q3(T), T))-.5208074999*(diff(q4(T), T)) = 0
EQ5 := .3183098860-1.041615857*q4(T)+3.088010748*q5(T)-0.6580284584e-4*(diff(q2(T), T))-0.8680125003e-1*(diff(q4(T), T))+0.8680125003e-1*(diff(q5(T), T)) = 0

with initial conditions:

q1(0) = 0, q2(0) = 0, q3(0) = 0, q4(0) = 0, q5(0) = 0, (D(q1))(0) = 0, (D(q2))(0) = 0, (D(q3))(0) = 0

Hello my dear friends:

i will obtain value f(4) from below equation:(f is funciton of t)

f[0](t)=a*cos(omega*t)
f[n+1](t)=f[0](t)+(1/omega)*int((omega^2*f[n](tau)-f[n](tau)^3)*sin(omega*(t-tau)),tau=0..t)

THANKS...

Hi:

how obtain value a4 from below equation in maple:

a[0]=1

a[n+2]=a[0]+a[n+1]