@Markiyan Hirnyk Answer, what impression about you after you have removed my correspondence with Kitonum and kept silent?
And more, why do you climb into topics where your expertise leaves much to be desired?

@Markiyan Hirnyk Start with http://www.mapleprimes.com/posts/202821-Calculating-Link-Mechanisms, then read carefully my previous message, there http://www.mapleprimes.com/posts/200663-Spatial-Fourbar-Linkages-
And do not forget to share your successes in mastering MapleSim.

@Thomas Richard 

Thank you. It is known that for flat linkages there are many methods of calculation. I promote a universal method for all kinds of linkages and plan to write a paper in English and put on Maplesoft
I can show some the calculations that are unlikely to get be done in MapleSim, for example:
http://www.mapleprimes.com/posts/200663-Spatial-Fourbar-Linkages- 

Variant of animation nearer to a drawing

@vv  So are you talking about ... Well, turn to the desired angle. This is all done by hand

@vv  What kind of animation you say? I gave the main text of the program to the first animation (the program works on  Maple13). The only difference is in the color reproduction.
Another text to the first animation I have not.

@Markiyan Hirnyk What do you allow yourself, what is my name in the forum? Where all my correspondence with Kitonum in that section?
I urge you to behave properly and to eliminate all violations committed by you.

@Markiyan Hirnyk  And where are the other examples of their the links?  

Again in the form of pictures.

@Markiyan Hirnyk  Who is Alexei Ivanov?

Two more similar examples.

@Markiyan Hirnyk 

You, as always, "I heard a bell, but do not know where it is." Is this animation associated with the program  SPIRAL.mw, the moderator  You ours? 

@Kitonum Compilation based on your answer and Thomas Richard

a := [1, 2, 3, 4, 5];
k := parse(cat(op(a)));
whattype(k);
k/5;

@Bendesarts 

I think you yourself can easily get the kinematics of any point with texts of my programs in the first message. For example, rhs (a1), rhs (a2), rhs (a3) correspond to the coordinates of the green point (x1, x2, x3), then

 ((rhs (a1) (s + h) - rhs (a1) (s)) ^ 2+ (rhs (a2) (s + h) - rhs (a2) (s)) ^ 2+ (rhs (a3) (s + h) - rhs (a3) (s)) ^ 2)) ^ 0.5 / h  

will speed along the trajectory of the green point on the rules of numerical differentiation. Similarly calculate the speed of the other points. The second derivative corresponds to acceleration. That is, if we know the coordinates of any point of the mechanism at any time, we can calculate the necessary qualities: any angles, any velocity along any axis, and so on. If you remember, I was trying to ask you: what is the source of such huge trigonometric expressions in your messages?
The presented work (.pdf) was written in Russian, you can try is to translate it using Google-translator, or any other way. I have plans to write more details in English, but this takes time.

@Carl Love  Very grateful to you, especially for the English.

 Another example of different "input links".  Four-bar mechanism.