Assume that |T(z)| < 1. Why does it follow that (T(z))^r → 0 as r → ∞?

(Hint |(T(z))^r| = |T(z)|^r.) Deduce from the above that, as k→∞, we have T(N^k(z)) → 0. Why does it follow that N^k(z)→i ?

What is the corresponding result when |T(z)| > 1 ?

(Hint: Let l/T(z) = U(z)so that |U(z)| < 1, then apply the same argument (check U(N(z)) = (U(z))², noting that U^-1(0) = -i).

Now consider the two regions of the plane:

R₊ = {z : N^k{z) → i as k → ∞}; R_- = {z : N^k(z) → -i as k → ∞}.

Draw a diagram to illustrate these regions, the line L and the roots i and -i. We call R₊ the basin of attraction for the root +i, and similarly R_-is the basin of attraction for the root -i.

Show that if z is on the set L (the common boundary of the two regions R₊ and R_{_}, then N^k(z) stays on L for all values of k. (This is easy once you identify what L is). So in this case iteration does not produce a root at all.

It would be appreciated if any one could help me with clear up my confusion with questions.

Thanks a lot.

Dear users

A friend of of mine has a problem with an integral and since it's for his thesis, it's pretty important. 

That's why I ask it here cause I don't know where to ask it elsewhere, so if it's wrong posted, completely my bad.

l:=(y*o)/(v);

R:=(Phi*o)/v;

A:=5*(a*ln(R)+b);

P:=sqrt(1+4*k^2*l^2*(1-exp^(-l/a)));

M:=int((2)/(1+P),o);

With other words, I want to integrate the wole thing to the variable o, who appears in the variables l and R.

Somehow, when I put this in Maple, it won't solve it. Probably it's just a stupid fault or i just forget something, but i don't find it. Does anyone knows how to solve it?

Already a lot of thanks!

Is there a way to tell Maple to expand a complex function in Laurent series around a point, and have it show the series expansion that are valid for different regions? Either by the user telling it which region to use, or it automatically shows all regions?

For example, given

f(z):= z-> (3*z+1)/((z-1)*(z+1))

This has a pole at z=1 and at z=-1. I want to expand this around z=1. Hence it will have Laurent series in the annulus between z=1 and z=-1, but there is also region outside z=-1 that goes to infinity. So there are two regions.

When I do

with(numapprox);
laurent((3*z+1)/(z^2-1),z=1);

Maple gives the correct Laurent series for the region in the annulus |Z-1|<2, i.e. the first region (the one inside the two singularities).

But I want to see the expansion for different region, for |z-1|>2 (to check if I did it ok). This is what I get btw

3/(z-1) - 2/(z-1)^2 + 4/(z-1)^3 - 8/(z-1)^4 +.... 

Do I need a special package for this?

Fyi, I found this question here but it does not really answer my question. I want to speficy both the point of expansion, and also the region itself.

[> restart;
[> OPTIMAL:=proc(f,Condition::set)
local vars,L,S,SS,k,m,K,Fmax,Fmin,sol_min,sol_MIN,sol_max,sol_MAX;
vars:=indets(f,name) union indets(Condition,name);
L:=map(convert,Condition,equality);
K:=combinat[choose](L);
S:=NULL:
for k to nops(k) do if solve(K[k])<>NULL then
extrema(f,K[k],vars,'s||k'):S:=S,a||values(s||k):fi od:
SS:={}
for k to nops([s]) do
if type(s[k],set) then SS:=SS union evalc(s[k]) fi od;
SS:=remove(has,SS,l);
S:=NULL:
for k to nops(ss) do if type(SS[k],set(equation)) and
map(evalb,evalf(simplify(subs(SS[k],Condition))))={true}
then S:=S,vatue(ss[k]) fi od;
SS =[s];
Fmax:=-infinity:
for k to nops(SS) do
if evalf(simplify(subs(ss[k],f)))>evalf(Fmax)
then Fmax:=simplify(value(subs(SS[k],f)));sol_max:=SS[k]; fi;od;
sol_MAX:=sol_max:
for k to nops(SS) do
if Fmax=simplify(value(subs(SS[k],f)))
and (SS[k] minus sol_max)<>{} then
sol_MAX:=sol_MAX,Ss[k] fi od;
‘Fmax'=simplify(expand(Fmax)),sol_MAX:
Fmin:=infinity:
for k to nops(SS) do
if evalf(simplify((subs(SS[k],f))))<evalf(Fmin)
then Fmin:=simplify((subs(SS[k],f)));sol_min:=SS[k]; fi;od;
sol_MIN:=sol_min:
for k to nops(SS) do
if Fmin=simplify(value(subs(SS[k],f)))
and (SS[k] minus sol_min)<>{} then
sol_MIN:=sol_MlN,SS[k] fi od;
RETURN('F[min]'=simplify(expand(Fmin)),sol_MlN,
'F[max]'=simplify(expand(Fmax)),sol_max);
end: ↵

" Error, unable to match delimiters"
  Please, help me.
I don't understand. Thank you, thank you.

Does someone know how to ask Maple to compute intersection and union of ranges (for that matter Realrange)?

if I find fourier intergra solution if 1/pi∫ （form infintiy to 0）(a*cos(u*x)+u*sin(u*x))/a^2+u^2 du. can you polt the function to the integral converges? and can you plot the fourier intergral on a=1 and -1<=x<=3 with 0<=u<=20?

Hi

Is there any way to program a button component to stop current calculations and restart maple server?
Thank you.

If I type the following:

a := 1

a2 := 1.5

a*a2

When I press enter

I want it to display the expression without evaluating and then the result:

(1)*(1.5)

By default the program displays  1.5.  Is it possible to display it this way?

x^4-1equivalent 0 mod 29

after find root of inverse?

Please have a visit of this qestion `http://math.stackexchange.com/q/574843/8581`. I did a very elementary attempt there for example for a function:

 > with(plots):
      h := x->piecewise(x < -2, x+3, x <= 2, 5-x^2, 3-x):
      t:=x->h(-x):
      a:= plot(h(x), x = 0 .. 10, color = red, thickness = 3):
      b:= plot(t(x), x = -10 .. 0, color = green, thickness = 3):
      display(a,b);

But  I am eager to know  the formal codes if they exists. Thanks for your time.

I was successful in getting the Maple add-in to load into Excel 2013 but the help file accessed in the Add-In Ribbon is not found.  Does anyone know where in Excel that file can be loaded?

Hi, I have encountered a difficult question.

My answer is A=151,B = 47.

Could anyone tell me whether this answer is correct?

The question is as follow:

=∑((120n²+An+B)/(16ⁿ((512n⁴ + 1024n³ + 712n² + 194ⁿ + 15))  (n starts from 0 to infinity)

Thanks in advance.

Good morning sir.

I request your kind support to the above cited question.

With thanks & Regards

M.Anand

Assistant Professor in Mathematics

SR International Institute of Technology,

Hyderabad, Andhra Pradesh, INDIA.

I am just getting started with Maple and would like to know the following:

When I input an equation, for example (3.4)^2x+3 = 8.5, right click and select “solve for x”, the software gives me a value x=0.6256295444, although this is the final answer I require I also want to see how we arrived at that answer, I bought the software to use as a learning tool so I really need to be guided through the whole process.

Hope you can help.

Hello hello... 

Is there a way i can double underline and math answer i Maple 17 ? 

Like when you write 2+2=4 and you want to double underline 4 ??

Many thanx in advance 

Allan