I tried this as well but it didn't output any values for me, just the expressions in terms of t. My inputs were: c:=z-x=0; curveb:=[x=sin(t),y=cos(t),z=exp(t)]; checka2:=fsolve(subs(curveb,c),t=-2..2); The last line gave me this as the output: checka2 := fsolve(exp(t)-sin(t) = 0, t, -2 .. 2)

Thank you very much! This was exactly what I needed. But lets say I want to find intersections for just a certain length of the space curve, say t=-2..2, is there a way to do this? I figured I would have to add something into the fsolve command or maybe specify it somewhere else but I'm not sure how to do it.