@John May Thank you, I get an impression

@Markiyan Hirnyk 

Here is some Math: estimate the probability for a prime over that reduced alphabet in a given range of decimals, assuming a sequence of length d is contained, as discussed above.

NB: For other pictures note they are reduced to black+white first.

Indeed.

If one does not care for 'some garbage in the right lower corner' it is easy,
roughly the last 5 digits "1 = white" would be replaced to give some prime
(allowing all the decimals, else it may be as vv said).

For the "rest" my 'feeling' is: roughly 1/1000 of the numbers with 3900 decimals
are primes and 5 of the decimals are allowed. For the "black" occuring numbers
there are long sequences (40 places or so), so chances are good.

However I am too weak prove a precise statement. If it is needed at all. Just do it.

Just in case someone is not aware of it: search for the term "ASCII art".

Though I have not seen the restriction to the smaller alphabet before.

And I like the neat twist (changing the "black numerals" only).

copy+paste: this page is HTML, the clipboard keeps some of it and Maple's
standard interface cares for it. Either use classical or use an intermediate
step using a "dumb" text processor which throws away the "<br>" code.
No need to use commands.

For "image to ASCII image" (and ignoring the neat twist for a prime): do you have it as "stand alone" and as code only?

For example and to get a feeling (using o=1 in your first y) try

plot('SFloatExponent'(y), tt=-0.1 .. 0.1); # showing Tom's range

or

plot('SFloatExponent'(y), tt=-5 .. 5); # your range

What you see is the exponent base for 10, i.e. you need roughly ~ 50,000 decimals to print you value in tt=+5

I did it (with Digits=200 because of the high degree and expected magnitudes), converting to rational coefficients first (ok, I know the input only used 10 decimals). Find the solutions attached as text.

Plotting the pairs it seems to me that may originate from asking for zeroes of a polynomial with complex variables with conjugated solutions and one real solution.

MP_222647.txt

What you show here is a hypergeometric series, Sum( (function of n's and d's) * z^k ),

the (function of n's and d's) are the coefficients of the power series, which satisfy some conditions.

Your general case is often denoted by pFq, if the power series is extended beyond the unit circle and considered there as function.

If you can not resist the try to understand a bit by reading Wikipedia (and perhaps some links given there) for the most important case 2F1.

Then you may (or may not) see that pochhammer is just another way to write the coefficients using them instead of the Gamma function.

You will need some sound Math basics, say 2 years as Math student and perhaps an advisor.

Not sure whether that aimed but "one" more step reduces that to

(1/s/(s+thetac)*alpha1*(-A2+(s+thetac)*pinf)+(1/(s+thetac)^(1/2)*Dc*alpha1+Dc^(1/2))/
((Dc-Dp)*s-Dp*thetac)*A1)*
exp((-lh+x)*s^(1/2)/Dp^(1/2))/(s^(1/2)*Dp^(1/2)-Dp*alpha1)*Dp;

Please look at Maple's help first, start with EllipticE and look for variations. Have in mind, that various definitions are used in Math, usually Maple uses Abramowitz and Stegun or likewise http://dlmf.nist.gov/22

It is not really satisfactory, more a kind of workaround

For me deleting the output of "showstat(`convert/elsymfun`)" is a bit ... ahem ... useless.

However formally it is covered by the license, Art 8 "you shall not ... display ... to a Third Party the Software, any copy or portion thereof, in whole or in part, on a temporary or permanent basis" (at least it was in the EULA in 2011, I can not find the concurrent one).

A bit non-sensical in that case ...

... 2*gamma1^(1/2)/gamma2^(1/2)/Pi*EllipticK(1/gamma2*(-gamma1^2+gamma2^2)^(1/2)) for mu1 = mu2, no?

what is the correct result?

PS & edit: this 'is' the integral of 1/sqrt( P(x) ) over the Reals, P = polynomial of degree 4 without real zeros and all different (mu1=mu2, gamma1=gamma2) and certainly 'known', no?

a) Please provide code - not images (especially MMA or the textbook)

b) Maple - by design - does not simplify results of integration.