If you input integers then Maple should process on that input. Otherwise just use floats.

@Christopher2222 for sites with persistent troubles you may use https://en.wikipedia.org/wiki/Ungoogled-chromium

there are portable versions as well

Works for me too (Firefox and blocking advertising). Disabling "infinite scroll" however gives the first page only. Hm, a matter of taste I suppose

I marked it with the mouse and changed it through the menu bar (without further testing)

@sursumCorda 

Are you sure about RefineRoot? The help gives me the impression that it is for finding approximative roots.

Edit: I see, it brackets a root

@mmcdara how about this:

Download MP_237846_min_max_piecewise.mw

@vv Thanks - that solves it

I was trapped by numerics it seems

[seq(10.0^(20*n), n=2 .. 14)]:
[seq(expr, x in %)]:
evalf[1000](%): evalf[3](%);
[        64          104          144         183         223  
[-3.22 10  , -1.79 10   , -2.18 10   , 9.38 10   , 3.02 10   ,

          263         303         343         383         423  
  -1.08 10   , 3.41 10   , 1.07 10   , 2.35 10   , 3.16 10   ,

          462          503          543]
  -3.26 10   , -1.96 10   , -3.39 10   ]

@Rouben Rostamian  

It's not a bug, just the rationalized form of yours. And you will need to sum up to ~ 10^11 I think

p:=c*(a+b); dismantle(p);

or

ToInert(p); FromInert(%);

@mcouture Adblockers and Anti-Tracking are natural for educated web users expecting privacy. And there is a lot of snooping on https://www.maplesoft.com/Applications/ However the site can be used if anti tracking is configured with care (and time for that).

@Kitonum acer's approach works in 2017.3

x^x=1/sqrt(2); map(ln, %); solve(%);

Why do you think the double integral equals Pi?

And: how do you want Dirac( g(x) ) to be understood?

same in Maple 2023.2

@WA573 I do not see how your imgae relates to your sheet, so I ignore that.

For you sheet: as Carl Love already explained above your assumption(s) silently imply something

limit(y2, t=infinity) assuming (lambda1::real, lambda2::real) is answered to be lambda1 + lambda2 and not depending on n, so y3 = LREtools:-delta(y2, n) is zero, hence y4 is a for that assumption