Axel Vogt

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20 years, 222 days
Munich, Bavaria, Germany

MaplePrimes Activity


These are replies submitted by Axel Vogt

vv, a nice observation (what is your 'A' and why in [0,1]^2 ?) !

So, sursumCorda: what is known as estimation from above ?

What is the source for this task (and who said the supremum [not the maximum], i.e. may be on boundaries, equals 3) ?

For example both of the following give 3:

'fun'; subs(z=1/y, %): MultiSeries:-limit(%, y=0, right) assuming 0<x;

'fun'; subs(z=1/y, %): MultiSeries:-limit(%, y=infinity) assuming 0<x;

Use eq1 instead of eq

Your X1 depends on x and t, so the first plot command can not work. Look at the following: indets(X1, symbol);

Have you looked up the help for that command?

for that kind of postings you / one should earn a negative rating, it is more than lame

Just a remark and ignoring the problem with "timelimit":

If it does not finish within hours then for me it would be likely that concurrent Maple can not solve the integral as given. Probably I would accept that (especially: the result could be wrong) instead of hoping for "brute force". May be you could find a better input by analyzing the mathematical structure. Or restrictions for the parameter a. Or for the range of p.

Thank you for completing :-)

@delvin that are just those you uploaded

1.mw = Version 2023.2
2.mw = Version 2022.2

Note also that Psi might be understood as the Psi function of Maple

@andmail

That code looks by increments of 1e-4 until something is ok, needing ~ 9000 steps. Perhaps you better look for a zero finder in VBA, "bisection" is certainly available. Or use the goal seek in an Excel sheet

Setting X = x/C you can write it as 0 = x - C*sin(x), which is a special case of Kepler's equation,
https://en.wikipedia.org/wiki/Kepler%27s_equation

Now use suggestions from that Wiki article or search for VBA code.

From your pdf it is likely that it is Brent's minimizer. If you can not find it through your search engine then I can upload an old post of Devore from the usenet (= http://groups.google.com today). However in Maple you will not need that, I guess.

At least if I use MMA-online I get quick results. But they are not consistent:

https://www.wolframalpha.com/input?i=evalf%5B15%5D%28LerchPhi%281%2F10%2C+1%2C+1%2F2-100000000*I%29%29
~ 1.018518518518518×10^(-15) + 1.666666666666667×10^(-7) i
https://www.wolframalpha.com/input?i=evalf%5B45%5D%28LerchPhi%281%2F10%2C+1%2C+1%2F2-100000000*I%29%29
~ 3.055555555555555×10^(-15) + 5.000000000000000×10^(-7) i

Similar for the original task (see attached sheet)

MP_236256.mw

I changed the Title from "how to solve for lamda and r in this equtaions.?" to "how to solve cos * cosh = 1 ?"

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