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Saha

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3 years, 73 days
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Thanks for the timely help.But when I ap...

Saha 70
March 05 2024
0 0

Thanks for the timely help.

But when I apply this to another similar problem i'm  unable to plot the graph.

SCM2.mw

@Hullzie16 

Thanks a lot.Please help me to solve the...

Saha 70
February 28 2024
0 0

Thanks a lot.

Please help me to solve the below problem.I dont know what value should be given to f(1) in Boundary condition.I want downflow curve.

I dont know how to clear this.

my file is below.

HNF_3.mw

@mmcdara 

Thank you for your suggestion.Now i can ...

Saha 70
December 07 2023
0 0

Thank you for your suggestion.Now i can frame the series.@Carl Love 

@acer  Thanks a lot...

Saha 70
November 14 2023
0 0

@acer 

Thanks a lot

Thank you for your valuable suggestions....

Saha 70
November 03 2023
0 0

Thank you for your valuable suggestions.

 

 

@mmcdara 

How to Plot this?...

Saha 70
November 02 2023
0 0

Thank you very much for your help.But i couldn't make it to plot.I got an error .How to rectify this.

Here is a code.

A_correct_syntax_1.mw@mmcdara 

Thank you...

Saha 70
June 10 2023
0 0

After changing sin(x),as you said I get the solution.But still  I couldn't plot it

TFBE1.mw

How to solve this?...

Saha 70
June 09 2023
0 0

 I don't know how to  take sin x  and  can you please help to plot this.

In my problem,

u(x,0)=sin x  and

Take,  alpha =1, x belongs to R.

TFBE1.mw

Warning, expecting only range variable t...

Saha 70
June 09 2023
0 0

Thanks,How to get 2d-plot for this equation,i didn't get the plot for the problem.I couldn't solve this.Please Help me. Initial condition for the problem is

u[0](x)=sin (x)  and

Take,  alpha =1, x belongs to R.

Corrected maple code is

TFBE1.mw

@sand15 

Error, (in dsolve/numeric/process_input)...

Saha 70
June 04 2023
0 0

Thanks a lot.Similar problem,I don't have solution for this too,please give me some ideas.   or

Can you give the maple code for Shooting method/ Kellor Box Method for this problem.

my code is

mvp-1.mw

Error, (in dsolve/numeric/bvp/convertsys...

Saha 70
June 02 2023
0 0

How to clear this Error.

My code is

MVP-RK_Method.mw

Similar numerical solution...

Saha 70
June 02 2023
0 0

@mmcdara 

Thanks a lot .Can the above solution be obtained for this  system of equation.But i get this plot.Is this correct?

Here is the code.

SMMS_1.mw

R,L,C,E Values are not given here. &nbs...

Saha 70
May 07 2023
0 0

R,L,C,E Values are not given here.

 

 

 

 

 

@Carl Love 

@mmcdara  Thank you so much,your s...

Saha 70
April 10 2023
0 0

@mmcdara 

Thank you so much,your suggestions are very useful for me,This can be applied to my problem.

I did'nt get the plot,Please Help...

Saha 70
April 08 2023
0 0

ADM_TRY.mw
 

Thank you for your valuable suggestions to work this problem.I found out Adomian polynomials but i couldn't  plot  the series.
> 

restart
> 

with(LinearAlgebra):
> 

F := proc (x) options operator, arrow; x^2 end proc:
> 

u[0] := 1+t*e^(x+y);

1+t*e^(x+y)

  

(1+t*e^(x+y))^2

 (1)
> 

for n from 0 while n <= 6 do V[n] := (diff(F(sum(lambda^i*u[i], i = 0 .. n)), [`$`(lambda, n)]))/factorial(n) end do:
> 

lambda := 0;

0

 (2)
> 

for i from 0 while i <= n-1 do A[i] := V[i] end do;

(1+t*e^(x+y))^2

  

2*(1+t*e^(x+y))*u[1]

  

u[1]^2+2*(1+t*e^(x+y))*u[2]

  

2*u[1]*u[2]+2*(1+t*e^(x+y))*u[3]

  

u[2]^2+2*u[1]*u[3]+2*(1+t*e^(x+y))*u[4]

  

2*u[2]*u[3]+2*u[1]*u[4]+2*(1+t*e^(x+y))*u[5]

  

u[3]^2+2*u[2]*u[4]+2*u[1]*u[5]+2*(1+t*e^(x+y))*u[6]

 (3)
> 

for n from 0 to 1 do u[n+1] := (1/2)*(int(int(diff(add(u[i], i = 0 .. n), x, x)+diff(add(u[n], i = 0 .. n), y, y), t = 0 .. t), t = 0 .. t))+int(int(A[n], t = 0 .. t), t = 0 .. t) end do;

(1/6)*e^(x+y)*ln(e)^2*t^3+(1/12)*(e^(x+y))^2*t^4+(1/3)*e^(x+y)*t^3+(1/2)*t^2

  

(1/60)*(e^(x+y))^2*ln(e)^2*t^6+(1/10)*((1/8)*e^(x+y)*ln(e)^4+(1/4)*e^(x+y)*ln(e)^2)*t^5+(1/12)*e^(x+y)*ln(e)^2*t^3+(1/252)*(e^(x+y))^3*t^7+(1/6)*((1/30)*(e^(x+y))^2+(2/5)*e^(x+y)*((1/6)*e^(x+y)*ln(e)^2+(1/3)*e^(x+y)))*t^6+(1/5)*((1/12)*e^(x+y)*ln(e)^2+(5/12)*e^(x+y))*t^5+(1/12)*t^4

 (4)
> 

v(t) := sum(u[r]*t^r, r = 0 .. 2);

1+t*e^(x+y)+((1/6)*e^(x+y)*ln(e)^2*t^3+(1/12)*(e^(x+y))^2*t^4+(1/3)*e^(x+y)*t^3+(1/2)*t^2)*t+((1/60)*(e^(x+y))^2*ln(e)^2*t^6+(1/10)*((1/8)*e^(x+y)*ln(e)^4+(1/4)*e^(x+y)*ln(e)^2)*t^5+(1/12)*e^(x+y)*ln(e)^2*t^3+(1/252)*(e^(x+y))^3*t^7+(1/6)*((1/30)*(e^(x+y))^2+(2/5)*e^(x+y)*((1/6)*e^(x+y)*ln(e)^2+(1/3)*e^(x+y)))*t^6+(1/5)*((1/12)*e^(x+y)*ln(e)^2+(5/12)*e^(x+y))*t^5+(1/12)*t^4)*t^2

 (5)
> 

plot(v(t), x = .101 .. .109);

Warning, expecting only range variable x in expression 1+t*e^(x+y)+(1/6*e^(x+y)*ln(e)^2*t^3+1/12*(e^(x+y))^2*t^4+1/3*e^(x+y)*t^3+1/2*t^2)*t+(1/60*(e^(x+y))^2*ln(e)^2*t^6+1/10*(1/8*e^(x+y)*ln(e)^4+1/4*e^(x+y)*ln(e)^2)*t^5+1/12*e^(x+y)*ln(e)^2*t^3+1/252*(e^(x+y))^3*t^7+1/6*(1/30*(e^(x+y))^2+2/5*e^(x+y)*(1/6*e^(x+y)*ln(e)^2+1/3*e^(x+y)))*t^6+1/5*(1/12*e^(x+y)*ln(e)^2+5/12*e^(x+y))*t^5+1/12*t^4)*t^2 to be plotted but found names [e, t, y]

  

 
> 

``


 

Download ADM_TRY.mw

@mmcdara 

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