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Zahrah Doughty

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14 years, 75 days
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These are replies submitted by Zahrah Doughty

This is my second attempt.Really need he...

Zahrah Doughty 0
April 22 2011
0 0

@hirnyk 

de1 := diff(f(x),x$2) - diff(g(x),x) + g(x)   =sin(x);

                   / 2      \
                   |d       |   /d      \
            de1 := |--- f(x)| - |-- g(x)| + g(x) = sin(x)
                   |  2     |   \dx     /
                   \dx      /

> ics := f(0) = 2, g(0)=1,D(f)(0) = -1 , f(x) ;

            ics := f(0) = 2, g(0) = 1, D(f)(0) = -1, f(x)

> 
> plot1( Y1, x = 0..Pi/2 ) ;

                      plot1(Y1, x = 0 .. 1/2 Pi)

> 
> 
> 
> 
> de2:=diff(g(x),x)-g(x)+f(x)
> =cos(x);

                      /d      \
               de2 := |-- g(x)| - g(x) + f(x) = cos(x)
                      \dx     /

> 
> ics := f(0) = 2, g(0)=1,D(f)(0) = -1 , f(x) ;

            ics := f(0) = 2, g(0) = 1, D(f)(0) = -1, f(x)

> plot2(Y2,x=0..Pi/2);

                      plot2(Y2, x = 0 .. 1/2 Pi)

>

This is my second attempt.Really need he...

Zahrah Doughty 0
April 22 2011

@hirnyk 

de1 := diff(f(x),x$2) - diff(g(x),x) + g(x)   =sin(x);

                   / 2      \
                   |d       |   /d      \
            de1 := |--- f(x)| - |-- g(x)| + g(x) = sin(x)
                   |  2     |   \dx     /
                   \dx      /

> ics := f(0) = 2, g(0)=1,D(f)(0) = -1 , f(x) ;

            ics := f(0) = 2, g(0) = 1, D(f)(0) = -1, f(x)

> 
> plot1( Y1, x = 0..Pi/2 ) ;

                      plot1(Y1, x = 0 .. 1/2 Pi)

> 
> 
> 
> 
> de2:=diff(g(x),x)-g(x)+f(x)
> =cos(x);

                      /d      \
               de2 := |-- g(x)| - g(x) + f(x) = cos(x)
                      \dx     /

> 
> ics := f(0) = 2, g(0)=1,D(f)(0) = -1 , f(x) ;

            ics := f(0) = 2, g(0) = 1, D(f)(0) = -1, f(x)

> plot2(Y2,x=0..Pi/2);

                      plot2(Y2, x = 0 .. 1/2 Pi)

>

Okay.This is what I have.Hope you can he...

Zahrah Doughty 0
April 22 2011
0 0

@hirnyk 

ode1:=D(D(f))(x)-D(g)(x)+g(x)=sin(x);dsolve(ode1,g(x));
                      (2)
            ode1 := (D   )(f)(x) - D(g)(x) + g(x) = sin(x)


                  /         / 2      \
                 |          |d       |
  g(x) = exp(x)  |  exp(-x) |--- f(x)| - exp(-x) sin(x) dx
                 |          |  2     |
                /           \dx      /

         + exp(x) _C1

> 
> ode2:=D(g)(x)-g(x)+f(x)=cos(x);dsolve(ode2,g(x));

                ode2 := D(g)(x) - g(x) + f(x) = cos(x)


                   /
                  |
   g(x) = exp(x)  |  -exp(-x) f(x) + exp(-x) cos(x) dx + exp(x) _C1
                  |
                 /

> 
> 
> dsolve({ode1,g(0)=1},g(x));dsolve({ode2,g(0)=1},g(x));

                   x
                  /          / 2      \
                 |           |d       |
  g(x) = exp(x)  |   exp(-u) |--- f(u)| - exp(-u) sin(u) du + exp(x)
                 |           |  2     |
                /            \du      /
                  0


                     x
                    /
                   |
    g(x) = exp(x)  |   -exp(-u) f(u) + exp(-u) cos(u) du + exp(x)
                   |
                  /
                    0

Okay.This is what I have.Hope you can he...

Zahrah Doughty 0
April 22 2011

@hirnyk 

ode1:=D(D(f))(x)-D(g)(x)+g(x)=sin(x);dsolve(ode1,g(x));
                      (2)
            ode1 := (D   )(f)(x) - D(g)(x) + g(x) = sin(x)


                  /         / 2      \
                 |          |d       |
  g(x) = exp(x)  |  exp(-x) |--- f(x)| - exp(-x) sin(x) dx
                 |          |  2     |
                /           \dx      /

         + exp(x) _C1

> 
> ode2:=D(g)(x)-g(x)+f(x)=cos(x);dsolve(ode2,g(x));

                ode2 := D(g)(x) - g(x) + f(x) = cos(x)


                   /
                  |
   g(x) = exp(x)  |  -exp(-x) f(x) + exp(-x) cos(x) dx + exp(x) _C1
                  |
                 /

> 
> 
> dsolve({ode1,g(0)=1},g(x));dsolve({ode2,g(0)=1},g(x));

                   x
                  /          / 2      \
                 |           |d       |
  g(x) = exp(x)  |   exp(-u) |--- f(u)| - exp(-u) sin(u) du + exp(x)
                 |           |  2     |
                /            \du      /
                  0


                     x
                    /
                   |
    g(x) = exp(x)  |   -exp(-u) f(u) + exp(-u) cos(u) du + exp(x)
                   |
                  /
                    0

Yeah.It's my homework....

Zahrah Doughty 0
April 22 2011
0 0

Yeah. It's a homework. I've tried doing the question this morning. Im not sure whether it is correct or not. I have an integral in my solution. Im gonna try again later. Thanks for your help. =))

Yeah.It's my homework....

Zahrah Doughty 0
April 22 2011

Yeah. It's a homework. I've tried doing the question this morning. Im not sure whether it is correct or not. I have an integral in my solution. Im gonna try again later. Thanks for your help. =))

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