Yes, you are right, but I pointed out that error calculation of Li(1) is not consistent with the answers of FunctionAdvisor definition "with no restriction on (z)" and with the FunctionAdvisor "special values " [Li(0)=0,Li(1)=-infinity,Li(infinity)=infinity]. This is just a technical, not a mathematical remark…

Yes, you are right, but I pointed out that error calculation of Li(1) is not consistent with the answers of FunctionAdvisor definition "with no restriction on (z)" and with the FunctionAdvisor "special values " [Li(0)=0,Li(1)=-infinity,Li(infinity)=infinity]. This is just a technical, not a mathematical remark…