The following is true 'sum(min(2, j)/factorial(j), j = 1 .. infinity)' = 'sum(min(2, j)/factorial(j), j = 1 .. 2)' +'sum(min(2, j)/factorial(j), j = 3 .. infinity)'; But Maple 11.01 thinks it isn't. The answer it gives is 2*exp(1)-2 = -3+2*exp(1) The answer on the right is correct. One the left, Maple seems to think that min(2,j)=2 (which is correct except for the first term in the sum). The problem doesn't seem to arise for finite sums.