Scott ,thank you so much for replying my questions.

I tried the way you are using to find coefficients.However, the results I get is differenct with what you have obtained.Here are what  I have tried:

restart; with(Statistics): Ein:=Vector([0,0.2,0.4,0.5,0.6,0.7,0.8,0.9,0.92,0.95,1,1.02,1.04,1.06,1.08,1.1,1.12,1.14,1.16,1.178]): UEin:=Vector([0,0.01576213,0.629139894,1.457776151,2.958910418,5.605599058,10.20002179,17.77607359,19.57451259,22.81827108,29.34874031,32.35324584,35.41703504,39.08008982,42.71086444,46.46475176,50.53683716,55.48548924,60.4973377,64.70966192]): Emax:=1.52: Fit(.5*A*E^2+B*E^beta/(Emax-E)^alpha, Ein, UEin, E);

-85.806303325380*E^2+92.6229168965963652*E^2.03381404705712621/(1.52-E)^.332390778517891283

Don't know what could be the reason why we have different output. I have currently useing Maple 11 if this helps. Also, using the fit function,is there a minimum vector input data ?As you can see I am trying to get 4 coefficients?Does it also mean if we have more input data, the coefficients will also be different? Thanks again Sam

Anyone know how to do this?

It works now Thank you!!So when we us fsovle command the rang of variables has to be carefully chosen, right?

hi Alec

I tried the method you useing above to solve my euations.However,I got the following error information::

Error, cannot split rhs for multiple assignment

Don't know why when you sovle them you don't have this

Sam

Just wondering if the case is:

when i=1 we have p=1,q=2,f=.3 If the equation is different let's say more complicated.Then we will have more than one result of q1 and q2.will it be a problem when i=1 to n??

Great great help from you guys I keep wondering how to sovle this.Thanks again!

Thank you for explanation!

If I have p,q,f is a group of data say:p=[12,3], q=[2,3,4], f=[.3,.4.5] correspondingly which means that when p=1,q=2,f=.3.Is it possible to  sovle such case and get a group of p1,p2??

Thank you Alec!