snhaseela2

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HELP : got unable to store error...

Asked: snhaseela2 10 Product: Maple 13

July 19 2016

2 2

Hi everyone!

I have a problem solving the nonlinear ode (as attached below). I got this error ---> Error, (in fproc) unable to store '-1.32352941215398+(-0.441176470717993e-1, -0.)' when datatype=float[8]

1) Could someone please explain to me what does the unable store .... error means?

and i will be grateful if you could help me finding the solution out. Thanks in advance

How to solve BVP by shooting method?...

Asked: snhaseela2 10 Product: Maple 13

June 08 2016

2 9

Hi everyone,

I'm kinda new here, and I really hope you guys can help me through this. In my new case study, after some revision, i thought i might be trying to implement a shooting method. I tried my best to make it work/understand but i couldn't get to any result.

So, as attached (i re-do PV Satya Naraya's paper first to be more understand but .....)

Here is my questions and the worksheet:

1) really stuck in mind - what is the purpose of shooting method for some related study?

2) what is the meaning of error .............'use midpoint method intead"

3) Worksheet - 1MASS_JEFF_SATYA_on_Beta.mw

Thanks in advanced. Really hope that someone can help/teach me how to solve the boundary value problem by shooting method.

restart; with(plots); lambda := 1.0; m := 2.0; M := 2; R := .1; Pr := .75; G := .1; Sc := .6; Kr := .2; blt := 5

Eq1 := diff(f(eta), eta, eta, eta)+(1+lambda)*(f(eta)*(diff(f(eta), eta, eta))-(diff(f(eta), eta))^2)-(1+lambda)*M*(diff(f(eta), eta))+beta*((diff(f(eta), eta, eta))^2-f(eta)*(diff(f(eta), eta, eta, eta, eta))) = 0;

diff(diff(diff(f(eta), eta), eta), eta)+2.0*f(eta)*(diff(diff(f(eta), eta), eta))-2.0*(diff(f(eta), eta))^2-4.0*(diff(f(eta), eta))+beta*((diff(diff(f(eta), eta), eta))^2-f(eta)*(diff(diff(diff(diff(f(eta), eta), eta), eta), eta))) = 0

(1)

Eq2 := (1+(4/3)*R)*(diff(theta(eta), eta, eta))+Pr*(f(eta)*(diff(theta(eta), eta))-m*(diff(f(eta), eta))*theta(eta)+G*theta(eta)) = 0;

1.133333333*(diff(diff(theta(eta), eta), eta))+.75*f(eta)*(diff(theta(eta), eta))-1.500*(diff(f(eta), eta))*theta(eta)+0.75e-1*theta(eta) = 0

(2)

diff(diff(phi(eta), eta), eta)+.6*f(eta)*(diff(phi(eta), eta))-1.20*(diff(f(eta), eta))*phi(eta)-.12*phi(eta) = 0

(3)

(4)

(5)

for k to 4 do R := dsolve(eval({Eq1, Eq2, Eq3, bcs1}, beta = L[k]), [f(eta), theta(eta), phi(eta)], numeric, output = listprocedure); Y || k := rhs(R[3]); YA || k := rhs(R[6]); YB || k := rhs(R[5]); YC || k := -rhs(R[8]) end do